(a) Express - 2x = 6 - 3y in standard form. (b) Indicate the values of a , b and c. (C) Check if (- 2, - 3) is a solution of the above equation is.
Answers
Answer:
(a) -2x + 3y - 6 = 0
(b) a = -2, b = 3 and c = -6
(c) No
Step-by-step explanation:
(a) the standard form of an equation is ax + by + c = 0
Hence to write in standard form, transpose all the R.H.S to L.H.S to get a zero on the R.H.S
(b) According to ax + by + c = 0, the value of a is the coefficient of x, the value of b is the coefficient of y and the value of c is the constant term. If the variable term is negative, then the value of x, y and constant term can also be negative. In -2x + 3y - 6 = 0, in the place of a, we have -2. Therefore the value of a is -2. In the place of b, we have 3, so the value of b is 3 and the constant term, i.e. c, is negative and hence its value is -6.
(c) (-2, -3) are coordinates (x, y). So, -2 is x and -3 is y.
-2 × x + 3 × y - 6 = 0
Putting the values of x and y in the equation, we get:-
-2 (-2) + 3 (-3) - 6 = 0
4 - 9 - 6 = 0
4 - 15 = 0
-11 ≠ 0
Since, L.H.S is not equal to R.H.S, (-2, -3) is not a solution of the equation -2x + 3y - 6 = 0