A exterior angle of an triangle is 110degree and one of the interior opposite angles is 30degree . Find the measure of other two angles of the triangle.
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Heya!!
We know that,
Sum of the measures of the interior opposite angles= The measure of exterior angle.
So,
Let the unknown angle be x.
30°+x°=110°
x°= 110°-30°
x°=80°
So the other angle is of measure 80°.
Now,
The measure of the third angle would be 180-(80+30).
Since, sum of all the angles of a triangle is 180°.
So here's the solution:
180-(80+30)
180-110
70°
So the angles measures are as follows:
Angle 1: 30°
Angle 2: 80°
Angle 3: 70°
Hope helped!!
We know that,
Sum of the measures of the interior opposite angles= The measure of exterior angle.
So,
Let the unknown angle be x.
30°+x°=110°
x°= 110°-30°
x°=80°
So the other angle is of measure 80°.
Now,
The measure of the third angle would be 180-(80+30).
Since, sum of all the angles of a triangle is 180°.
So here's the solution:
180-(80+30)
180-110
70°
So the angles measures are as follows:
Angle 1: 30°
Angle 2: 80°
Angle 3: 70°
Hope helped!!
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