Question

(a) f(x2) = x3 + x2 + x + 1, x > 0, find f(16). ​

Answer 1

Answer:

Step-by-step explanation:

Please clarify if this question is

f(x^2)=x^3+x^2+x+1

If this is questions then put x=16

i.e. f(16^2)=16^3+16^2+16+1

f(256)=4096+256+16+1

f(256)=4369

Answer 2

Answer:

85

Step-by-step explanation:

Given,    f(x²) = x³ + x² + x + 1

We need to find f(16), so

Let such a case where x² = 16

               ⇒ x = 4 or -4

As given,  x > 0   (x can't be -ve)

     ∴ x = 4

Therefore,   for x = 4

⇒ f(4²) = (4)³ + (4)² + (4) + 1

⇒ f(16) = 64 + 16 + 4 + 1

           = 85