Question

A face centred cubic element (at mass = 60) has cell edge 400 nm. What is its density ?​

Answer 1

Explanation:

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Answer 2

Answer:

For fcc  (Zeff = 4)

Formula :- f = Z × M / a³ × Na

         f = Zeff * Aw / q³ * Na              

Avagardo number (Na) = (6.023 × 10²³)

        f = 4 * 60 / ( 400)³ × 16.023 × 10²³) × ( 10⁻¹⁰)³           ( 1 pm = 10⁻¹⁰ c m)

        f = 6.23 g/cm³