Question

a) Factorise: 16a2 - b2 - 2bc - c2​

Answer 1

Answer:

$\large\boxed{\sf{(4a+b+c)(4a-b-c)}}$

Step-by-step explanation:

Given that, to factorise

$16 {a}^{2} - {b}^{2} - 2bc - {c}^{2}$

Simplifying Futher

$= 16 {a}^{2} - ( {b}^{2} + 2bc + {c}^{2} ) \\ \\ = 16 {a}^{2} - {(b + c)}^{2} \\ \\ = {(4a)}^{2} - {(b + c)}^{2} \\ \\ = (4a + b + c)(4a - b - c)$

Concept Map:-

• ${x}^{2} + 2xy + {y}^{2} = {(x + y)}^{2}$

• ${x}^{2} - {y}^{2} = (x + y)(x - y)$

Answer 2

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