Question

A factory employs 100 workers. of these, 36 workers earn a wage of $410 per day and the rest earn a wage of $360 per day. If the factory runs for 6 days in a week, how much does it pay each week?

Answer 1

Answer:

$4620

Step-by-step explanation:

36 workers earn - $410 per day

64 workers earn - $360 per day

total pay of all employees in one day - 410+360 = $770

total pay of 1 week = 770x6

                               = $4620

Answer 2

Answer:

It pays each week $25500 amount.

Step-by-step explanation:

Given,A factory employs 100 workers

Therefore total number of workers = 100.

Now it is also given,36 workers earn a wage of $410 per day.

So, per day income of 36 workers is $410

Therefore by Unitary method,they will income in 6 days

$(410 \times 6) = 2460$

Again given that the rest earn a wage of $360 per day

Rest number of employee = $(100 - 36) = 64$

Wage of 64 persons in 1 days is $360.

Therefore,wages of 64 persons in 6 days will be $(360 \times 64) = 23040$

Therefore the company has to pay every 6 days to his employee = (23040+2460) = $25500

This is a problem of Algebra related.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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2) https://brainly.in/question/1169549

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