Question

A factory has 10 bulbs,12fans and 2 air conditioner. Each bulb draws 50W,the fan draws 40W and the air conditioner draws 100W. On the average all the bulbs are kept on for 10 hours,fans for 15 hours and the air conditioner for 5 hours. Find the cost of electric energy used in a month at the rate of ₹5/- per KWH

Answer 1

Answer:Rs. 1908/- + Taxes

Explanation:

Bulbs - 5kw/day

Fans - 6.72 kw/day

AirConditioner - 1 kw/d

12.72kw X 5Rs (As per the rate in Question)

= 63.6/- Per Day

On an average the month has 30 days

63.6/- X 30

= 1908/-

Answer 2

The Cost of electrical energy using the given data for a month is Rs. 1980.

1) Given data,

Power drawn by the 10 bulbs= 10 * 10 * 50 Watt- hr = 5000 watt hr

Power drawn by the 12 fans = 12 * 15 * 40 watt - hr = 7200 watt hr

Power drawn by the 2 air conditioner = 2 * 5 * 100 watt - hr = 1000 watt - hr

2) So, total power utilized = 5000 + 7200 + 1000 = 13200 watt - hr = 13.2 Kwatt- hr

3) Cost generated per month = 13.2 * 5 * 30 = Rs 1980