A factory is supplied with power at 210 volts through a pair of feeders of total resistance 0.0225 Ω. The load consists of 354, 250 V, 60 watt lamps and 4 motors each taking 40 amperes. Find :
(i) total current required
(ii) voltage at the station end of feeders
(iii) power wasted in feeders.
Answers
Answer:
A factory is supplied with power at 210 volts through a pair of feeders of total resistance 0.0225 ohms.The Load consists of 250v,60watts lamp and 4 motors each taking 40amperes each.
Find
(i) Total current required
(ii) Voltage at the station end of feeders
(iii) Power wasted in feeders
Answers:
(i) 231.40 amps
(ii) 215.78 volts
(iii) 1.4 KW
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Given : A factory is supplied with power at 210 volts through a pair of feeders of total resistance 0.0225 Ω. The load consists of 354, 250 V, 60 watt lamps and 4 motors each taking 40 amperes.
To Find : (i) total current required
(ii) voltage at the station end of feeders
(iii) power wasted in feeders.
Solution:
The load consists of 354, 250 V, 60 watt lamps
250V , 60W lamp
P = V²/R
=> 60 = 250²/R
=> R = 250²/60
Voltage Supplied = 210V
I = V/R
=> I = 210/(250²/60)
=> I = 210 * 60 / 250²
=> I = 126/625
354 Bulbs
I = 354 x 126/625
=> I = 71.3664 A
4 motors each taking 40 amperes. = 4 x 40 = 160A
Total current = 71.3664 + 160 = 231.3664
voltage at the station end of feeders = 210 + I(0.0225 )
= 210 + (231.3664 )(0.0225 )
= 210 + 5.205744
= 215.205744
= 215.2 V
power wasted in feeders = I²(0.0225 )
= 1,204.43 W
= 1.2 KW
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