Physics, asked by adityaanurag531, 3 months ago

A factory is supplied with power at 210 volts through a pair of feeders of total resistance 0.0225 Ω. The load consists of 354, 250 V, 60 watt lamps and 4 motors each taking 40 amperes. Find :

(i) total current required

(ii) voltage at the station end of feeders

(iii) power wasted in feeders.

Answers

Answered by jyosankori
0

Answer:

A factory is supplied with power at 210 volts through a pair of feeders of total resistance 0.0225 ohms.The Load consists of 250v,60watts lamp and 4 motors each taking 40amperes each.

Find

(i) Total current required

(ii) Voltage at the station end of feeders

(iii) Power wasted in feeders

Answers:

(i) 231.40 amps

(ii) 215.78 volts

(iii) 1.4 KW

Why i posted the answers is?

I tried in 2 to 3 ways but i couldn't able to get the correct answers...

Please spare some time to post the process of solving this problem ...

So that it will help an enthusiastic learner to learn ahead.....

Waiting for the solution .....

I would be glad if you do answer me..

Thanks in advance!! Cheers!!!!!!!

Answered by amitnrw
7

Given : A factory is supplied with power at 210 volts through a pair of feeders of total resistance 0.0225 Ω. The load consists of 354, 250 V, 60 watt lamps and 4 motors each taking 40 amperes.

To Find : (i) total current required

(ii) voltage at the station end of feeders

(iii) power wasted in feeders.

Solution:

The load consists of 354, 250 V, 60 watt lamps

250V  , 60W lamp

P = V²/R

=> 60  = 250²/R

=> R =  250²/60

Voltage Supplied = 210V

I = V/R

=> I  = 210/(250²/60)

=> I = 210 * 60 / 250²

=> I  = 126/625

354 Bulbs

I = 354 x   126/625

=> I  = 71.3664 A

4 motors each taking 40 amperes. = 4 x 40 = 160A

Total current =  71.3664 + 160 = 231.3664

voltage at the station end of feeders = 210 + I(0.0225 )

= 210 + (231.3664 )(0.0225 )

= 210 + 5.205744

= 215.205744

= 215.2   V

power wasted in feeders  = I²(0.0225 )

= 1,204.43 W

= 1.2  KW

Learn More:

A current of 0.30 A flows through a resistance of 500Ω. How much ...

https://brainly.in/question/12604100

https://brainly.in/question/33134963

Similar questions