Question

A factory makes 4250 bars of chocolate. There were three kinds of chocolate bars creamy.milky ad white.The number of white chocolate bars was 715 more than the number of milky chocolate bars. The number of creamy chocolate bars was 5 times the number of milky chocolate bars.how many creamy chocolate bars did the factory make? explain with details ​

Answer 1

Answer:-

x = $\frac{3535}{11}$

Step-by-step explanation:-

LET THE NUMBER OF MILKY CHOCOLATES BE x

⇒ NUMBER OF CREAMY CHOCOLATES = 5x

AND,

NUMBER OF WHITE CHOCOLATE BARS = 5x + 715

∵ TOTAL NUMBER OF CHOCOLATES = 4250

∴ x + 5x + 5x + 715 = 4250

→ 11x = 3535

⇒ x = $\frac{3535}{11}$

||MrCuteKing||

Answer 2

total bars of chocolate=4250

creamy:- x

milky:- y

white:- z

white was 715 more than milky

z=715+y ---------1

x=5(y) ------------2

x+y+z = 4250

5y + y + 715 + y = 4250

7y + 715 = 4250

7y = 4250 - 715

7y = 3535

y = 505 (i.e. milky bars)

putting value of y in equation 2

x = 5y

x = 5×505

x = 2525

therefore no of creamy chocolates is 2525

x+y+z = 4250

2525+505+y = 4250

3030+y = 4250

y = 1220

Verification of creamy chocolate

it ja given that creamy chocolate is 5 times milky chocolate

and 2525 is 5 times 505

hope it helps you