A factory manufactures 1500 pencils daily. The pencils are cylindrical in shape each of length 25 cm and circumference of base as 1.5 cm. Find the cost of
colouring the curved surfaces of the pencils manufactured in one day at Rs 5 per dm²
Answers
Given :
ㅤㅤㅤ➪ Total pencils = 1500
ㅤㅤㅤ➪ = 25 cm
ㅤㅤㅤ➪ = 1.5 cm=2πr
ㅤㅤㅤ➪ per cm² = Rs 5
To Find :
- Cost of colouring the Curved surface of all the pencils produced in the factory in one day
Formula Usable :
- = 2πrh
•°• Solving the problem :
ㅤㅤ➪ C.S.A of the pencil = 2πr h
ㅤㅤ➪ㅤ "ㅤㅤ"ㅤ"ㅤㅤ"ㅤ= (1.5)×h [given]
ㅤㅤ➪ㅤ "ㅤㅤ"ㅤ"ㅤㅤ" ㅤ = 1.5 × 25
ㅤㅤ➪ㅤ "ㅤㅤ"ㅤ"ㅤㅤ" ㅤ = 37.5 cm²
Now ,
- Cost of colouring of all the pencils produced in a day
- Total length of all pencil ➪
ㅤㅤㅤㅤㅤㅤ= 1500 × 37.5 m
ㅤㅤㅤㅤㅤㅤ= 56250.0 m
ㅤㅤㅤㅤㅤㅤ= 56250 m
•°• Cost of colouring all the pencils produced in one day :
ㅤㅤㅤ➪ 5 × 56250
ㅤㅤㅤ➪ Rs
_____________________
More to remember :
- C.S.A of cylinder = 2πrh
- T.S.A of cylinder = 2πr(r+h)
ㅤㅤㅤ
ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂
Given :
ㅤㅤ ㅤ➪ Total pencils = 1500
ㅤㅤㅤ
To Find :
Cost of colouring the Curved surface of all the pencils produced in the factory in one day
Formula Usable :
•°• Solving the problem :
ㅤㅤ➪ C.S.A of the pencil = 2πr h
ㅤㅤ➪ㅤ "ㅤㅤ"ㅤ"ㅤㅤ"ㅤ= (1.5)×h [given]
ㅤㅤ➪ㅤ "ㅤㅤ"ㅤ"ㅤㅤ" ㅤ = 1.5 × 25
ㅤㅤ➪ㅤ "ㅤㅤ"ㅤ"ㅤㅤ" ㅤ = 37.5 cm²
Now ,
Cost of colouring of all the pencils produced in a day
Total length of all pencil ➪
ㅤㅤㅤㅤㅤㅤ= 1500 × 37.5 m
ㅤㅤㅤㅤㅤㅤ= 56250.0 m
ㅤㅤㅤㅤㅤㅤ= 56250 m
•°• Cost of colouring all the pencils produced in one day :
ㅤㅤㅤ➪ 5 × 56250
ㅤㅤ
_____________________
More to remember :
C.S.A of cylinder = 2πrh
T.S.A of cylinder = 2πr(r+h)
ㅤㅤㅤ
ㅤㅤ