A factory manufacturing electric bulbs increases the the production Uniformly by a fixed number every month if in the third month production is 600 electric bulbs and in the 7th month production is 800 electric bulbs then find the total production of electric bulbs in the year.
Answers
Answered by
1
Answer:
8700
Step-by-step explanation:
here we get
a=450 d=50
hence
S12=12/2 (2×450 + (11×50)
=6×(900+550)
=6×1450
=8700
Answered by
1
Answer:
9300
Step-by-step explanation:
3rd month production =600 (given)
a+2d=600 -----(1)
7th month production =800( given)
a+6d=800 ------(2)
subtracting (1) from (2) we get d=50 and substituting d=50 in any one equation we get a=500
total production = n/2 [2a+(n-1)d]
= 12/2 [2(500) +(12-1) 50
=6 ( 1000+550 )
=6(1550)
=9300
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