Math, asked by bgsenthilkumar1977, 2 months ago

A factory produced 12,345 dolls in the first week. The next week it produced

22,160. If 2456 dolls were defective, how many dolls were not defective?

answer this fast​

Answers

Answered by MrM00N
6

Step-by-step explanation:

Let the original number of dolls be x.

Given, Number of defected dolls = 20x/100

Given, Number of Remaining dolls = 80x/100

Number of remaining were damaged = 25% of 80x/100

                                                               = 20x/100

Number of toys left over = 

x - (20/100 * x + 20x/100) = 4800

x - 40x/100 = 4800

100x - 40x/100 = 4800

60x/100 = 4800

x = 4800 * 100/60

   = 8000.

The original number of dolls was 8000.

Hope this helps!

Answered by architasingh8b
1

Answer:

No. of dolls factory produced in 1 week= 12,345

Next week's production= 22,160

If we add them then we got= 34505

Now no. of dolls which were defective= 2456

If we will subtract the no. of defective dolls from producted doll we will get the answer..which is:

No. of dolls not defective = 34505-2456=32049

Step-by-step explanation:

32049 is the answer

Hope it helps you

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