Math, asked by pp1803234, 17 days ago

A factory produces 2985 bulbs in a day. How many bulbs did it produces in the year 2008 if there were 68 holidays in the year ?

Answers

Answered by ambitamach

0

Step-by-step explanation:

step 1 - 2008 is a leap year so total no of days in that year is 366

step 2- subtract the holidays with the total no of days

366-68= 298

step 3- multiply the bulbs produced in a day with 298.

2985x298= 8,88,530

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