Question

A factory produces 8000 toys through three machines. The machine two produced 20% the toys, the machine three produced 1800. A toy is selected at random and it was defective, what is the probability that it was from machine three if the defective % for machine one, machine two and machine three are 1%, 0.5% and 0.5% respectively.

Answer 1

Answer

Step-by-step explanation:
Factory produced 8000 toys
Two machines produced 20% of toys.
So they produced =1,600 toys.
Third machine produced 1800 toys
Total number of working and fine toys = 1,600+1,800=3,400 toys.
Toys which are bad and not working properly= 8000-3400=4600 toys.
Rest of your question is not understood

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