Question

A factory produces electric bulbs if one out of every 10 bulbs is defective, and the factory produces 630 bulbs per day find the number of defective bulbs produced each day?
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Answer 1

A factory produces 1 defective bulb out of every 10. Thus the probabilty of producing a defective bulb is 0.1

Total bulbs it produces are 630.

Hence the defective bulbs are 0.1×630=63

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Answer 2

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.