Question

A fair coin is tossed 12 times. What is the probability that

Answer 1

Answer:

Your question is incomplete.

Answer 2

if your question is to 8times ahead so the answer is

There are 12 tosses made with coin which have two possibilities either head or tail .Given, out of 12 tosses ,there should be atleast eight consecutive heads [i.e, event (8H,4T) or (9H,3T) or (10H,2T) or (11H,1T) or (12H)]

So,there are five events in which their probability will be added to get the probability of getting atleast eight consecutive heads.

E(8H,4T)=C(12,8)=495

E(9H,3T)=C(12,9)=220

E(10H,2T)=C(12,10)=66

E(11H,1T)=C(12,11)=12

E(12H)=C(12,12)=1

P( atleast eight consecutive heads)

=(495+220+66+12+1)/4096

= 794/4096