a fair coin is tossed 8 times. Find the probability of getting no head and at least one head
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Given :
a fair coin is tossed 8 times
To find :
the probability of getting
- no head
- at least one head
Solution :
a fair coin is tossed thrice
so, simple space
= 2³
= 8
I. e. (HHH) ,( HHT), (HTH) ,(THH) , (HTT), (THT), (TTH), (TTT)
1) No head
= (TTT)
= 1
probability = ⅛
2) at least one head
= (HHH) ,( HHT), (HTH) ,(THH) , (HTT), (THT), (TTH)
= 7
Probability = 7/8
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