Question

A fair dice is rolled twice and the face values are noted what is the probability that the product of the face values will be an even number

Answer 1

Answer:

3/4

Step-by-step explanation:

P( product is even )

= P( at least one number was even )

= 1 - P( both numbers were odd )

= 1  -  P( first number odd ) × P( second number odd )

= 1 - (1/2)×(1/2)

= 1 - 1/4

= 3/4

Answer 2

Here the dice is rolled twice.

Hence the possible outcomes are,

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,2 6,3 6,4 6,5 6,6

Hence No.of possible outcomes -- 36

Favourable outcomes are as follows,

1,2 1,4 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,2 3,4 2,6

4,1 4,2 4,3 4,4 4,5 4,6

5,2 5,4 5,6

6,1 6,2 6,3 6,4 6,5 6,6

Hence no. of favourable outcomes---- 27

{because face value must be even. that means in the two attempts at least one it should be even}

Hence as per the formula,

---------- 27/36

i.e 3/4