Question

A fair die is tossed once. Find the probability of getting:
a) a number more than or equal to 3.
b) a multiple of 3

Answer 1

Answer:

a) 4/6 = 2/3

b) 2/6 = 1/3

Answer 2

Answer:

1. the probability of getting number more than 3 or equal to 3 = 4(3,4,5,6)
2. total number of outcome = 6(1,2,3,4,5,6,7,8,9)
3. so, the probability =favorable no of outcome /total no of outcome
4. =4/6 =2/3
5. (b) multiple of 3=(2×3)(3×2) (only 2 outcome)
6. so probability = 2/6
7. =1/3 Answer........