Question

A fair spinner is placed at the centre of the circle. Diameter AOB and radius OC divide the circle into three
regions labelled as X, Y and Z. If ZBOC = 60°, what is the probability that the spinner will land in the region Y?
60°
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Answer 1

Step-by-step explanation:

Given ∠BOC = 45° ∠AOC = 180° – 45° = 135° Area of circle = πr2 Area of region X = θ/360°x πr2 = 135/360 x πr2 = 3/8 x πr2 Probability that the spinner will land in the region X = (Area of region of x)/(total area of circle) = (3/8 x πr2)/πr2 = 3/8Read more on Sarthaks.com - https://www.sarthaks.com/102746/in-the-accompanying-diagram-a-fair-spinner-is-placed-at-the-center-o-of-the-circle?show=102773#a102773