Question

a falcon is diving at a speed of 30m/s .it accelerates at a rate of 40m/s^2 and reaches a speed of 100m/s.calculate the distance it travels during its acceleration​

Answer 1

"A falcon is diving at a speed of 30m/s .It accelerates at a rate of 40m/s^2 and reaches a speed of 100m/s."

Here, initial velocity or speed of the falcon is 30 m/s, final velocity is 100 m/s and acceleration due to gravity is 40 m/s².

We have to find the distance travelled by falcon.

First equation of motion:

v = u + at

Second equation of motion:

s = ut + 1/2 at²

Third equation of motion:

v² - u² = 2as

From above data we have, v = 100 m/s, u = 30 m/s and a = 40 m/s². Substitute them in the third equation of motion to find the value of distance 's'.

Using the Third Equation Of Motion,

v² - u² = 2as

→ (100)² - (30)² = 2(40)(s)

→ 10000 - 900 = 80s

Take 10 as common on both sides,

→ 10(1000 - 90) = 10(8s)

→ 1000 - 90 = 8s

→ 910 = 8s

→ 910/8 = s

→ 113.75 = s

Therefore, the distance covered by the car is 113.75 m.

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 30 m/s

Final velocity, v = 100 m/s

Acceleration, a = 40 m/s²

To Find,

Distance traveled, s = ?

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (100)² - (30)² = 2 × 40 × s

⇒ 10000 - 900 = 80s

⇒ 9100 = 80s

⇒ 9100/80 = s

⇒ s = 113.75 m.

Hence, the distance traveled by falcon is 113.75 m.