A family comprised of an old man 6 adults and 4 children is to be seated in a row with the condition that children would occupy both the ends and never occupy either side of the old man how many seating arrangements are possible
Answers
Answered by
3
The correct answer is 4! X 5! X 7!
Step-by-step explanation:
- There are a total of 10 people and 10 seats out of them 6 are adults and 4 are children.
- The children will be side seated in 2 ways.
- On the other hand, the old man will take middle seats and they can not take 2nd and 10th seat.
- Therefore, required number of ways .
- = 4C2 x 2! x 7 x 6P2 x 6!
- = 6x2x7x30x720
- =1814400
Answered by
3
Answer:
The correct answer is 4! X 5! X 7!
Step-by-step explanation:
There are a total of 10 people and 10 seats out of them 6 are adults and 4 are children.
The children will be side seated in 2 ways.
On the other hand, the old man will take middle seats and they can not take 2nd and 10th seat.
Therefore, required number of ways
.
= 4C2 x 2! x 7 x 6P2 x 6!
= 6x2x7x30x720
=1814400
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