Math, asked by sowjanyaharsha11, 6 months ago

a family has 4 members.the sum of father and son is 50 years.the ratio of the Father and daughter 6years back is 16:5.the ratio of the mother and daughter 4years later is 9:5.find present age mother.if the daughter is 4years elder to the brother

Answers

Answered by Manurajhada10
0

Step-by-step explanation:

so let

father's age = x

son's age = y

and

x+y = 50

y= 50-x

now daughter is 4 years elder than son

= 50-x +4 = 54 - x

now father and daughter ratio 6yrs back

= x-6 = 16

54-x-6 5

5(x-6) = 16( 48- x)

5x-30 = 768-16x

21x = 798

x = 38

so age of son

= 50 -38 = 12

and daughter's age

12 + 4 = 16

now let mother's age be = y

so ratio of mom to daughter age 4 years hence

= y+4 = 9

16+4 5

5(y+4) = 9×20

5y +20 = 180

5y = 160

y = 32 answer .

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