Question

A family has two cars. During one particular week, the first car
consumed 50 litres of petrol; the second car consumed 100 litres
of petrol. The two cars drove a combined distance of 1500 km
and the sum of their fuel efficiencies was 25 km per litre.
Represent the above situation algebraically and solve
graphically to find the efficiencies of each car during that week.
Also, if the efficiency of first car is 10 km per litre then find the
efficiency of the second car.

Answer 1

Answer:

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Step-by-step explanation:

so the 1st car is 10 km per litter

50 x 10 = 500 so the first car traveled 500 km

so the 2nd car is 25 km per lite

100 x 25 = 2500 km