A family of 5 persons can be maintained for 20 days with ₹2,480. Find, how long will ₹6,944 maintain a family of 8 persons? direct and inverse variations
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Given
Total members in 1st case(M) =5
Day(D) =20
Money(₹) =₹2480
In case 2nd members(m) =8
Money(Rs) =₹6944
To find days in 2nd case=d
Using
MD/₹ =md/rs


d=35days
This is ur ans hope it will help you in case of any doubt comment below
Total members in 1st case(M) =5
Day(D) =20
Money(₹) =₹2480
In case 2nd members(m) =8
Money(Rs) =₹6944
To find days in 2nd case=d
Using
MD/₹ =md/rs
d=35days
This is ur ans hope it will help you in case of any doubt comment below
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