Math, asked by tokaians, 1 year ago

A family of 5 persons can be maintained for 20 days with Rs.2480.Find How long Rs.6944 maintain a family of 8 persons?

A group of labourers promises to do a piece of work in 10 days,but five of them  become absent.if the remaining labourers complete the work in 12 days,Find their original number in the group

Answers

Answered by kvnmurty
8
maintenance for one person per day = Rs 2480 / 20 days / 5  = Rs 24.80
Call this m = Rs 24.80  / person / day

Maintenance for 8 persons  =  8 m =   Rs 198.40 / day
Num of days Rs 6944  can maintain 8 persons  =  6944  /  198.40  = 35 days

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let N members in the group. Total work = W
    Work capacity of one member  = W / (10 * N)   per day
Remaining group =  N-5 members
Work done by remaining group = 12 *  (N-5)* W / (10 *N)   =  W 
                 12 * (N-5)  = 10 N    =>  2N = 60  => N = 30

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