A family of 5 persons can be maintained for 20 days with Rs.2480.Find How long Rs.6944 maintain a family of 8 persons?
A group of labourers promises to do a piece of work in 10 days,but five of them become absent.if the remaining labourers complete the work in 12 days,Find their original number in the group
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maintenance for one person per day = Rs 2480 / 20 days / 5 = Rs 24.80
Call this m = Rs 24.80 / person / day
Maintenance for 8 persons = 8 m = Rs 198.40 / day
Num of days Rs 6944 can maintain 8 persons = 6944 / 198.40 = 35 days
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let N members in the group. Total work = W
Work capacity of one member = W / (10 * N) per day
Remaining group = N-5 members
Work done by remaining group = 12 * (N-5)* W / (10 *N) = W
12 * (N-5) = 10 N => 2N = 60 => N = 30
Call this m = Rs 24.80 / person / day
Maintenance for 8 persons = 8 m = Rs 198.40 / day
Num of days Rs 6944 can maintain 8 persons = 6944 / 198.40 = 35 days
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let N members in the group. Total work = W
Work capacity of one member = W / (10 * N) per day
Remaining group = N-5 members
Work done by remaining group = 12 * (N-5)* W / (10 *N) = W
12 * (N-5) = 10 N => 2N = 60 => N = 30
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