A family photograph has a length 14 2/5 cm and breadth 10 2/5 cm. It has border of uniform width 2 3/5 cm. Find the area of the farmed photograph.
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Answers
Step-by-step explanation:
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Given data : A family photograph has a length 14 ⅖ cm and breadth 10 ⅖ cm. It has border of uniform width 2 ⅗ cm.
To find : The area of the farmed photograph ?
Solution :
According to given data,
⟹ length of photograph = 14 ⅖ cm
⟹ length of photograph = 14 * 5/5 + 2/5
⟹ length of photograph = 70/5 + 2/5 cm
⟹ length of photograph = (70 + 2)/5 cm
⟹ length of photograph = 72/5 cm
similarly;
⟹ breadth of photograph = 10 ⅖ cm
⟹ breadth of photograph = 10 * 5/5 + 2/5 cm
⟹ breadth of photograph = 50/5 + 2/5 cm
⟹ breadth of photograph = (50 + 2)/5 cm
⟹ breadth of photograph = 52/5 cm
similarly;
⟹ width of uniform border = 2 ⅗ cm
⟹ width of uniform border = 2 * 5/5 + 3/5 cm
⟹ width of uniform border = 10/5 + 3/5 cm
⟹ width of uniform border = (10 + 3)/5 cm
⟹ width of uniform border = 13/5 cm
Now, the length and breadth of the photograph when the width of the border is added to it.
⟹ length of photograph with width = 72/5 + 13/5 + 13/5
⟹ length of photograph with width = 85/5 + 13/5
⟹ length of photograph with width = 98/5 cm
similarly;
⟹ breadth of photograph with width = 52/5 + 13/5 + 13/5
⟹ breadth of photograph with width = 65/5 + 13/5
⟹ breadth of photograph with width = 78/5 cm²
Now,
⟹ Area of the farmed photograph = 98/5 * 78/5
⟹ Area of the farmed photograph = 7644/25 cm²
Answer : Area of the farmed photograph is 7644/25 cm² ( 305.76 cm²).