Question

A family uses 8 bulbs of 60 W each for 6 hours every day and 4 fans each of 60 W each for 12 hours every day when connected to 200 V main. Calculate the monthly bill (30 days) if energy costs ₨ 2 per Kwh. What should be the fuse rating for the above-mentioned devices?

Answer 1

ANSWERS :-

GIVEN ,

Power of each bulb = 100 W ,

power of each fan = 60W

time = 10 hour each day

Now ,

power of two bulbs = 2 * 100. = 200W

power of two fans = 2 * 60 = 120 W

so,

total power = 200 + 120

= 320 W

or,

total power = 320/1000 KW = 0.32 kW

time consumption in a month = 10 h * 30

= 300 hour

so,

total energy consumed

= Total power * time duration

= 0.32 kW * 300 h

= 0.32 * 300/100

= 32 * 3

= 96 kWh

__________________________

❤BE BRAINLY ❤

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Answer 2

$\huge\sf\pink{Answer}$

☞ Money bill will be ₹633.6

☞ Fuse rating = 3.6 A

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$\huge\sf\blue{Given}$

✭ A family uses 8 bulbs of 60 W each for 6 hours

✭ And 4 fans of 60 W each for 12 hours

✭ Time = 30 days

✭ Cost per kwh = ₹2

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$\huge\sf\gray{To \:Find}$

◈ Monthly bill?

◈ Fuse rating for the above mentioned devices

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$\huge\sf\purple{Steps}$

We know that the commercial unit of electrical energy is Kwh so we shall first convet all W to Kw

➢ $\sf1000 W = 1 Kw$

➢ $\sf60 W = \dfrac{60}{1000}$

➢ $\sf0.06 Kw$

In the case of bulbs

➝ $\sf8 \times 0.06$

➝ $\sf P = 0.48 Kw$

Also the time will be,

➝ $\sf6 \times 30$

➝ $\sf T = 180 \ hours \ per \ month$

In the case of fans

➝ $\sf4 \times 0.06$

➝ $\sf P = 0.24 Kw$

The time here will be,

➝ $\sf12 \times 30$

➝ $\sf T = 360 \ hours \ per \ month$

Total Power Consumed

➠ 0.48 + 0.24

➠ Power = 0.72 Kw

Total time they have run

➠ 180 + 360

➠ Time = 440 Hours

Electrical Energy Consumed

The Electric energy is given by,

$\sf\underline{\boxed{\sf Electric \ Energy = Power \times Time}}$

Substituting the given values,

➳ $\sf E = 0.72 \times 440$

➳ $\sf\green{316.8 \ Kwh}$

The Money Bill will be

➳ $\sf2 \times 316.8$

➳ $\sf\red{Money \ Bill = Rs \ 633.6}$

Fuse Rating for the above mentioned devices

We know that,

$\sf\underline{\boxed{\sf P = VI}}$

◕ P = 60 × 4 + 60 × 8 = 720 W

◕ V = 200 V

On substituting the values,

»» $\sf720 = 200 \times I$

»» $\sf\dfrac{720}{200} = I$

»» $\sf\orange{Fuse \ Rating = 3.6 A}$

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