Physics, asked by crazyyu, 1 year ago

A family uses 8 kilowatt of power.
a.direct solar energy is incident on the horizontal surface at an average rate of 200 watt per square metre .if 20% of the energy can be converted to useful electrical energy how large an area needed to supply 8kW.

b. compare this area to that of the roof of a house constructed on a plot of side 20m *15 m with the permission to cover up to 70%

Answers

Answered by rockyak4745
7
(a) Power used by the family, P = 8 kW = 8 × 103 W

Solar energy received per square metre = 200 W
Efficiency of conversion from solar to electricity energy = 20 %
Area required to generate the desired electricity = A
As per the information given in the question, we have:
8 × 103 = 20% × (A × 200)
= (20 /100) × A × 200
∴ A = 8 × 103 / 40  =  200 m2

(b) The area of a solar plate required to generate 8 kW of electricity is almost equivalent to the area of the roof of a building having dimensions 14 m × 14 m. (≈ √200).

Answered by TheEmpress
41
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