Question

A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ m0 of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes:........PLSSS ANSWER ILL MARK AS BRAINLIEST

Answer 1

$m \: m0 \div \sqrt{1 - v { }^{2} } \div {m}^{2}$

m=m0/√[1-v²/m²]

hope it helps