Question

A fan is making 600 revolutions/minute. If it makes 1200 revolutions/minute, what is the increase in its angular velocity?
(1) 10 it rad/sec
(2) 20 tt rad/sec
(3) 60 i rad/sec
(4) 40 r rad/sec​

Answer 1

Answer:

ω=600×

60

2π

=20π rad/s

ω is doubled if it takes 1200 rpm

ω

0

=

60

1200×2π

=40π rad/s

∴Δω=ω

0

−ω =20π rad/s

Explanation:

2) one

Answer 2

Solution :

u = 2π ( n₂ - n₁ )

$\sf = \dfrac{2\pi \times 600}{60}$

= 20π

So , the answer is (2) → 20 tt rad/sec