a fan is roteting at 90 rpm it is then switched off.it stoppes after 21 revolution.calculate the time taken by it to stop assuming that the frictional torque is constant.
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Answered by
60
Answer: t= 28s.
Explanation:
n0 = 90rpm 1.5rps
∴ ω = 2pi n0 = 3pi rad/s
The angle through which the blades of the fan move while
the blades of the fan move while stopping is theta = 2piN = 2pi(21) = 42 pi rad, ω = 0 (fan stops).
Using eyuations analoguos to kinematical equations of motion
α = ω - ω0/t = ω^2 - ω0^2/2theta
∴0-3pi/t = 0-(3pi)^2/2(42pi)
∴t = 28s.
Answered by
108
Answer:
Explanation:
Sum is explained in below attachment....
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