Question

A fan of moment of inertia 0.6kg/m2 is to run up to a working speed of 0.5 rps. The correct

value of angular momentum of fan (in kgm2/s) is:-

a. 0.6 b. 6 c. 3 d.



⁄​

Answer 1

Answer:

A fan of moment of inertia 0.6

Explanation:

Angular momentum=Iω=0.6×0.5×2π=0.6πkg metre²/sec

 

​ A fan of moment of inertia 0.6kgm2 is moving with a speed of 0.5 r.p.s. The angular momentum of the fan .

Answer 2

Given :-

• Moment of inertia (l) = 0.6 km/m²
• Angular velocity (ω) = 0.5 rps

To Find :-

• Angular momentum of a fan.

Solution :-

As we know that,

L = I × ω

Here,

• L = Angular momentum
• I = Moment of inertia
• ω = Angular velocity

[ Put the values ]

↪ L = 0.6 × 0.5 × 2π

↪ L = 0.3 × 2π

↪ L = 0.6 π kg.m²s-¹

Therefore,

Angular momentum of a fan is 0.6 π kg.m²s-¹.