A far-sighted man cannot focus distinctly on objects closer than 75 cm. What is the power of the lens that
will permit him to read from a distance of 40 cm?
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Answer:
Given,
Near point, v=−75cm
Reading Distance, u=−40cm
From lens formula,
- 1/f = 1/v - 1/u
- = 1/-75 - 1/-40
- = 7/600
- = 0.011
f=+0.011
Focal length of lens f=+0.011cm
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