Question

a farm house having 400 cows have provision of food for 200 days how many cows must be sold after 40 days so that the remaining food last for 200 days more for the remaining cows​

Answer 1

Answer:

Let the food will now last for x days. Then,

Let the food will now last for x days. Then, Number of animals 20 30

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 x

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last.

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.∴ 20 × 6 = 30x ⇒ x =

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.∴ 20 × 6 = 30x ⇒ x = 30

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.∴ 20 × 6 = 30x ⇒ x = 3020×6

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.∴ 20 × 6 = 30x ⇒ x = 3020×6

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.∴ 20 × 6 = 30x ⇒ x = 3020×6 = 4

Let the food will now last for x days. Then, Number of animals 20 30Number of days 6 xClearly, more is the number of animals, less will be the number of days for food to last. So, it is a case inverse proportion.∴ 20 × 6 = 30x ⇒ x = 3020×6 = 4 Hence, the food will now last for 4 days.