A farm in the shape of a trapezium whose parallel side are 120m and 154m. the non-parallel side are 50m and 52m. the owner of the farm wants to sell the plot. the market value is at rate of Rs 2 lakh m square. how much he can demand ?
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parallel sides of trapezium are 120 & 154
and non parallel sides are 50 & 52.
Area of trapezium = area of parallelogram + area of triangle.
Using Heron’s formula, Now, s = (a+b+c)/2 = (34+50+52)/2 = 68
On calculating we get, Area = 816 sq meter
Again area of triangle = (basexheight)/2 = (34Xheight)/2 = 816
So height = 48 meter,
Area of parallelogram = (sum of parallel sidesXheight)/2 =5760
Total area of trapezium = 5760 + 816 = 6576 sq meter
Total cost = Rs 2,00000 X 5760 = Rs1315200000
and non parallel sides are 50 & 52.
Area of trapezium = area of parallelogram + area of triangle.
Using Heron’s formula, Now, s = (a+b+c)/2 = (34+50+52)/2 = 68
On calculating we get, Area = 816 sq meter
Again area of triangle = (basexheight)/2 = (34Xheight)/2 = 816
So height = 48 meter,
Area of parallelogram = (sum of parallel sidesXheight)/2 =5760
Total area of trapezium = 5760 + 816 = 6576 sq meter
Total cost = Rs 2,00000 X 5760 = Rs1315200000
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