Question

A farmar move along the boundary of a square field of side 8m in 32 s. What will be the magnitude of the displacement of the farmar at the end of 1 min 20 sec.

Answer 1

Explanation:

let's find the velocity first...

distance of square field = 8m

time = 32s

speed=8/32 m/s

=0.25 m/s

now his displacement ,as he travels with same speed so,

v=0.25m/s. t=1min20sec=80sec

displacement=velocity*time

=0.25*80

=20m