Question

A farmar moves along the 10 m 40s ,what Will be the magnitude of displacement of the farmar at the end of 2minute 20 second from his initial position​

Answer 1

total time=2× 60 sec+20sec=140sec

distances covered in40 sec=40 m

distance covered in 140 s= 40m×140 sec /40sec=140metre

displacement = length of AC =

$10 \sqrt{2 }$