A farmer along the boundary of square field is 10 m 40 sec.What will be the magnitude of displacement of the Farmers at the end of 2 min 20 sec from his intive position
Answers
Answered by
1
Answer:10√2m
perimeter of the field = 40 m
Time taken for 1 lap = 40sec
Total time=2 min 20 sec = 140sec= (40+40+40+20)sec
In 20sec, displacement will be √{(10)^2+(10)^2}=√200 = 10√2m
Similar questions