Question

A farmer along the boundary of square field is 10 m 40 sec.What will be the magnitude of displacement of the Farmers at the end of 2 min 20 sec from his intive position​

Answer 1

Answer:10√2m

perimeter of the field = 40 m

Time taken for 1 lap = 40sec

Total time=2 min 20 sec = 140sec= (40+40+40+20)sec

In 20sec, displacement will be √{(10)^2+(10)^2}=√200 = 10√2m