Question

A farmer and his son used to sell 30 oranges each at the local market daily. The farmer used to
sell at the rate of 2 oranges for a rupee while his son, being poor at bargaining, used to sell at
the rate of 3 oranges for a rupee. They used to return with Rs.25 daily.
One day the farmer was sick and asked his son to go to the market alone. They decided that
since they used to sell 2 for a rupee and 3 for a rupee respectively, the effective rate should be
5 oranges for 2 rupees. So the son went and sold all the 60 oranges at the rate of 5 oranges
for 2 rupees, making Rs.24 in all!
How did the son end up making a loss of 1 rupee?
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Answer 1

Answer:

the reason is that the oranges with higher rate (2 o/₹) were sold less whereas oranges with higher rate(3 o/₹)

were sold more in nos.

Step-by-step explanation:

in second case farmer is actually asking his son to divide 60 oranges in baskets with 5 oranges each.

60÷5 = 12 such baskets

also, in each basket 2 of the 5 oranges are to be sold @ 2 o/₹

i.e. 2×12 = 24 oranges total from all 12 baskets

now this number in first case was 30, which now has been decreased to 24.

.

similarly remaining 3 of the 5 oranges in each basket to be sold @ 3 o/₹

i.e. 3×12 =36 oranges total from 12 baskets.

and this number was also 30 in first case, which now has been increased.