A farmer borrowed Rs.2400 @12% interest per annum. At the end of 2and1/2 years, he cleared his account by paying Rs.1200 and a cow. What is the cost of the cow?
Anonymous:
Principal = 2400
Rate of interst = 12 per annum
time = 2.5 years
First we will calculate simple interest
SI = p*R*T/100;
= 2400 *12*2.5/100
= 720.
SO Total amount To PAy at the end of 2.5 years= Principal + Simple Interest
= 2400 +720
= 3120
The borrower pays 1200 and Cow.
therefore ,
1200+COst of Cow = 3120
cost of cow = 3120 - 1200
Cost of cow = 1920.
Thanks You.
Answers
Answered by
108
Hi ,
Principal = P = Rs 2400
Rate of interest ( I ) = 12%
Time = T = 2 1/2 years = 5 /2 years
Amount = A
We know that ,
A = P ( 1 + TR /100 )
= 2400[ 1 + (5 × 12)/(2 × 100 )]
= 2400 × [ ( 100 + 60 ) /200 ]
= 2400 × 160 /200
A = RS 3120
According to the problem given ,
1200 + cost of cow = A
Cost of the cow = 3120 - 1200
= Rs 1920
I hope this helps .
:)
Principal = P = Rs 2400
Rate of interest ( I ) = 12%
Time = T = 2 1/2 years = 5 /2 years
Amount = A
We know that ,
A = P ( 1 + TR /100 )
= 2400[ 1 + (5 × 12)/(2 × 100 )]
= 2400 × [ ( 100 + 60 ) /200 ]
= 2400 × 160 /200
A = RS 3120
According to the problem given ,
1200 + cost of cow = A
Cost of the cow = 3120 - 1200
= Rs 1920
I hope this helps .
:)
Answered by
58
Principal, P = Rs. 2400
Rate of interest, I = 12%
Time, T = years
= 5/2 years
Amount, A = P ( 1 + TR /100 )
= 2400 x [1 + (5 × 12)/(2 × 100)]
= 2400 × [ ( 100 + 60 )/200 ]
= 2400 × 160 /200
= RS 3120
ATQ,
1200 + cost of cow = A
Cost of the cow = A - 1200
= 3120 -1200
= Rs 1920
hope it helps
@ankit1234
#moderator-brainly
Rate of interest, I = 12%
Time, T = years
= 5/2 years
Amount, A = P ( 1 + TR /100 )
= 2400 x [1 + (5 × 12)/(2 × 100)]
= 2400 × [ ( 100 + 60 )/200 ]
= 2400 × 160 /200
= RS 3120
ATQ,
1200 + cost of cow = A
Cost of the cow = A - 1200
= 3120 -1200
= Rs 1920
hope it helps
@ankit1234
#moderator-brainly
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