Math, asked by karthikeyan533, 1 year ago

A farmer borrowed Rs.2400 @12% interest per annum. At the end of 2and1/2 years, he cleared his account by paying Rs.1200 and a cow. What is the cost of the cow?

Anonymous: Principal = 2400

Anonymous: here principal = 2400
Rate of interst = 12 per annum
time = 2.5 years

First we will calculate simple interest
SI = p*R*T/100;
= 2400 *12*2.5/100
= 720.

SO Total amount To PAy at the end of 2.5 years= Principal + Simple Interest
= 2400 +720
= 3120

The borrower pays 1200 and Cow.
therefore ,
1200+COst of Cow = 3120
cost of cow = 3120 - 1200
Cost of cow = 1920.

Thanks You.

Answers

Answered by mysticd

108

Hi ,

Principal = P = Rs 2400

Rate of interest ( I ) = 12%

Time = T = 2 1/2 years = 5 /2 years

Amount = A

We know that ,

A = P ( 1 + TR /100 )

= 2400[ 1 + (5 × 12)/(2 × 100 )]

= 2400 × [ ( 100 + 60 ) /200 ]

= 2400 × 160 /200

A = RS 3120

According to the problem given ,

1200 + cost of cow = A

Cost of the cow = 3120 - 1200

= Rs 1920

I hope this helps .

:)

Answered by Ankit1234

Principal, P = Rs. 2400

Rate of interest, I = 12%

Time, T = $2 \frac{1}{2}$ years
= 5/2 years

Amount, A = P ( 1 + TR /100 )

= 2400 x [1 + (5 × 12)/(2 × 100)]

= 2400 × [ ( 100 + 60 )/200 ]

= 2400 × 160 /200

= RS 3120

ATQ,

1200 + cost of cow = A

Cost of the cow = A - 1200

= 3120 -1200

= Rs 1920

hope it helps

@ankit1234
#moderator-brainly

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