A farmer borrowed rupee2400at an interest of12% per annum at the end of 5/2 years he cleared his account by paying rupee1200 and a cow find the cost of the cow.
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Answered by
9
The money borrowed by the farmer (principal) = Rs 2400
Rate of Interest = 12% p.a.
Time (duration) of interest = 5/2 years
Interest = p * r * t / 100
= (2400 * 12 * 5/2) / 100
= 720
Amount = P + S.I.
= 2400 + 720
= Rs 3120
A/q,
=> Amount paid = 1200 + cost of cow
=> 3120 = 1200 + cost of cow
=> cost of cow = 3120 - 1200 = 1920
So, the cost of the cow is Rs 1920
Rate of Interest = 12% p.a.
Time (duration) of interest = 5/2 years
Interest = p * r * t / 100
= (2400 * 12 * 5/2) / 100
= 720
Amount = P + S.I.
= 2400 + 720
= Rs 3120
A/q,
=> Amount paid = 1200 + cost of cow
=> 3120 = 1200 + cost of cow
=> cost of cow = 3120 - 1200 = 1920
So, the cost of the cow is Rs 1920
Answered by
2
Dear Friend !!
A = Rs 4720
R = 12% p. a
T = 1 ½ years = 3/2 years
Recall the formula, A = P[1 + (TR/100)]
= 4720[ 1 + (3 × 12)/200]
= 6419.20
Hence the cost of the cow is Rs 6419.20
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