Question

A farmer borrows rs.1000 and agrees to repay with a total interest of rs.140 in 12 instalment each instalment being less than the preceding instalment by rs.10 what should be his first instalment

Answer 1

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Let the First Instalment be 'a'.
and second Instalment be '10-a'.
Since it will form an A.P.

The sum of ten Instalments = 10/2[2a + (10-1) (-10)] = 5[2a - 90]
So, 5 [2a-90] = 4000.
=    10a - 450 = 4000.
      10a = 4450.
          a = 4450/10
          a = 445.
First Instalment will be Rs. 445.

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Answer 2

Answer:

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