A farmer bought a buffalo for 45,000 and a cow for 20,000. He sold
the buffalo at a loss of 5% but made a profit of 10% on the cow. Find the
overall profit or loss in transaction.
Answers
Answer:
Cost price of buffalo =Rs.44000
Loss of 5%
∴Loss=
100
5
×44000=2200
Selling price of buffalo =Rs.44000−2200=Rs. 41800
Cost price of cow =Rs.18000
Profit of 10%
Hence,
profit=
100
10
×18000=1800
So, Price=18000+1800=Rs. 19800
Cost price of both cow and buffalo
=44000+18000=Rs. 62000
Selling price of both cow and buffalo
⇒Rs.(19800+41800)=Rs.61600
∴Loss=62000−61600=Rs.400
Step-by-step explanation:
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Answer:
Loss of ₹1250
Step-by-step explanation:
C.P of Buffalo= 45000
Loss%=5%
SP = 100-5% × 45000
100
= 95 ×450
= 42750
CP OF COW=20000
PROFIT% = 10%
SP= 100+10 × 20000
100
=110×200
=22000
TOTAL CP = 45000+20000
= 65000
TOTAL SP= 42750+22000
=64750
HERE CP>SP
LOSS= 65000-64750
= ₹1250
THE OVERALL LOSS IN TRANSACTION IS ₹1250