A farmer bought a buffalo for Rs. 4400 and a cow for Rs. 18000. He sold the buffalo at a loss of 5 % but made a profit of 10 % on the cow. Find out the net profit or loss on the whole transaction.
Answers
Answer:
Loss of Rs 400
Step-by-step explanation:
C.P. of buffalo = Rs. 44000
Loss on buffalo = 5 %
S.P. of buffalo = C.P. - loss
44000- 5\% \text { of } 44000=44000- \dfrac{5}{100} \times 44000=44000-2200=Rs. 4180044000−5% of 44000=44000−
100
5
×44000=44000−2200=Rs.41800
Now , C.P. of cow =Rs. 18000
Profit on cow = 10%
S.P. of cow = C.P. + Profit
18000+ 10\% \text{ of }18000=18000+ \dfrac{10}{100} \times 18000= 18000+ 1800=Rs.1980018000+10% of 18000=18000+
100
10
×18000=18000+1800=Rs.19800
Total C.P. = C.P. of buffalo + C.P. of cow= 44000+18000=Rs. 62000
Total S.P. = S.P. of buffalo +S.P. of cow= 41800+ 19800=Rs 61600
Now as we can see C.P. > S.P. so there is a loss
Loss = C.P. - S.P. = Rs. 62000- Rs.61600= Rs. 400
Hence, There is a loss of Rs. 400 in the net result of the transaction.
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