Question

A farmer bought a buffalo for Rs 44000 and a cow for Rs 18000. He sold the buffalo at a loss of 5% but made a profit of 10% on the cow. What is the net result of the transaction (Profit/Loss) and how much?

Answer 1

Step-by-step explanation:

Cost price of cow = ₹ 18000

Profit percent on cow = 10%

We know that, Profit percent =

(Profit/CP) × 100 10 = (Profit/₹ 18000) × 100 (10 × 18000)/100 = Profit Profit = 10 × 18

Then, Profit = SP – CP 1800 = SP – 18000 SP = 1800 + 18000 SP of cow = ₹ 19800

Cost price of buffalo = ₹ 44000

He sold the buffalo at a loss of 5%

We know that, Loss percent = (loss/CP) × 100 5 = (loss/44000) × 100 (5 × 44000)/100 = loss Loss = 5 × 440 Loss = ₹ 2200

SP of buffalo = ₹ 41,800 Now,

Total cost price of both buffalo and

cow = ₹ 44000 + ₹ 18000 = ₹ 62000

Total selling price of both buffalo and cow = ₹ 41800 + ₹ 19800 = ₹ 61,600

Selling price of both buffalo and cow is less when compare to cost price,

So, Loss = CP – SP = ₹ 62000 – ₹ 61600

Loss = ₹ 400