Question

a farmer bought a buffalo for Rupees 44000 and a cow for rupees 18000 he sold the buffalo at a loss of 5% what made a profit profit of 10% on the cow the net result of the transaction is

Answer 1

loss of
5percent of 44000 is
44000×5/100 = 2200
and gain of
10percent of 18000 is
18000×10/100=1800
so net transaction will be
=gain -loss
=1800-2200
= -400
so it is loss

Answer 2

Answer: Loss of Rs. 400

Step-by-step explanation:

C.P. of buffalo = Rs. 44000

Loss on buffalo = 5 %

S.P. of buffalo = C.P. - loss

$44000- 5\% \text { of } 44000=44000- \dfrac{5}{100} \times 44000=44000-2200=Rs. 41800$

Now , C.P. of cow =Rs. 18000

Profit on cow = 10%

S.P. of cow = C.P. + Profit

$18000+ 10\% \text{ of }18000=18000+ \dfrac{10}{100} \times 18000= 18000+ 1800=Rs.19800$

Total C.P. = C.P. of buffalo + C.P. of cow= 44000+18000=Rs. 62000

Total S.P. = S.P. of buffalo +S.P. of cow= 41800+ 19800=Rs 61600

Now as we can see C.P. > S.P. so there is a loss

Loss = C.P. - S.P. = Rs. 62000- Rs.61600= Rs. 400

Hence, There is a loss of Rs. 400 in the net result of the transaction.