Question

A farmer bought two cows for rs 18,500. he sold one at a loss of 20% and the other at a profit of 20%. if the selling price of each cow is the same, then their cost prices are respectively?

Answer 1

SP1=SP2
SP1 = 20% loss = 80% of CP
SP2 = 20% profit = 120% of CP
SP1/SP2 = 80/120 = 2/3
CP of two cows = 18500 rs
CP1 = 2*(18500/(2+3)) =7400 rs
CP2 = 3*(18500/(2+3)) = 11100 rs

Answer 2

Answer:

CP of cow 1 is Rs.11100 and CP of cow 2 is Rs.7400

Step-by-step explanation:

Let the cost price of 1 cow be x

A farmer bought two cows for rs 18,500.

So, CP of cow 2 = 18500-x

Case 1

CP of cow 1 = x

Loss% = 20%

$SP=\frac{CP(100-L\%}{100}$

$SP=\frac{x(100-20)}{100}$

$SP=\frac{80x}{100}$

Case 2

CP of cow 1 = 18500-x

Profit% = 20%

$SP=\frac{CP(100+P\%}{100}$

$SP=\frac{(18500-x)(100+20)}{100}$

$SP=\frac{120(18500-x)}{100}$

We are given that the selling price of each cow is the same

So, $\frac{80x}{100}=\frac{120(18500-x)}{100}$

$x=11100$

So, CP of cow 1 is Rs.11100

CP of cow 2 = Rs.18500-Rs.11100=Rs.7400

Hence CP of cow 1 is Rs.11100 and CP of cow 2 is Rs.7400