A farmer buys a plot of agricultural land for Rs 450000. He sells one-third at a loss of 15%
and two-fifth at a gain of 20%. At what price must he sell the remaining land, so as to make
an overall profit 10%.
Answers
Answer:
for easy solving, I take his total land as 90 acres.
so,he buys 90 acres at 4,50,000.
given,he sells 1/3 rd at loss of 15%,
if 90acres ---->4,50,000,
then 1/3 means 30acres, should be sold at (450000*30)/90,
=1,50,000.
but he sells at loss of 15%,
that means he get only 85% of 1,50,000,i.e,(85*1500)=1,27,500.
given,he sells 2/5 th of land at 20% gain,
2/5 th land means 36 acres,
actually,36acres should be sold at (450000*36)/90,
=1,80,000
but he sold and gain 20%,that means he get 120%of 1,80,000, i.e,(12*18000)=2,16,000.
given,he should get 10%overall profit by selling remaining land,
remaining land will be 90-(30+36)=24acres.
10%profit over 4,50,000 means, 4,95,000
therefore,
1,27,500+2,16,000+X=4,95,000,
=>X = 1,51,500,
so he should sell the remaining land at 1,51,000.
Hope it helps u...
Answer:
First Method
CP = 3600000.
To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.
1/3 of the land sold on 20% loss.
SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.
SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.
SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.