Math, asked by kemily5799, 10 months ago

A farmer buys a plot of agricultural land for Rs 450000. He sells one-third at a loss of 15%
and two-fifth at a gain of 20%. At what price must he sell the remaining land, so as to make
an overall profit 10%.

Answers

Answered by nalanagulajagadeesh
21

Answer:

for easy solving, I take his total land as 90 acres.

so,he buys 90 acres at 4,50,000.

given,he sells 1/3 rd at loss of 15%,

if 90acres ---->4,50,000,

then 1/3 means 30acres, should be sold at (450000*30)/90,

=1,50,000.

but he sells at loss of 15%,

that means he get only 85% of 1,50,000,i.e,(85*1500)=1,27,500.

given,he sells 2/5 th of land at 20% gain,

2/5 th land means 36 acres,

actually,36acres should be sold at (450000*36)/90,

=1,80,000

but he sold and gain 20%,that means he get 120%of 1,80,000, i.e,(12*18000)=2,16,000.

given,he should get 10%overall profit by selling remaining land,

remaining land will be 90-(30+36)=24acres.

10%profit over 4,50,000 means, 4,95,000

therefore,

1,27,500+2,16,000+X=4,95,000,

=>X = 1,51,500,

so he should sell the remaining land at 1,51,000.

Hope it helps u...

Answered by mohanyadav10784
0

Answer:

First Method

CP = 3600000.

To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.

1/3 of the land sold on 20% loss.

SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.

SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.

SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.

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