A farmer buys a tractor for Rs. 70000 and after using it for
some time , he sells it at a loss of 5% to another farmer. He also
sells it after an year to the third farmer at a loss of 10%. Find
the price paid by the third farmer.
Answers
Answered by
4
for 1st farmer-
CP = 70000
SP =(95/100)×70000=66500
for 2nd farmer-
CP= 66500
SP=(90/100)×66500=59850
For 3rd farmer -
CP=59850
CP = 70000
SP =(95/100)×70000=66500
for 2nd farmer-
CP= 66500
SP=(90/100)×66500=59850
For 3rd farmer -
CP=59850
Answered by
0
Soln:- for 1st farmer
S.P=C.P(1-loss℅/100)
=70000(1-5/100)
=70000(19/20)
=66500
for second farmer
S.P=C.P(1-loss℅/100)
=66500(1-10/100
=66500(9/10)
=59850
So the third farmer had to pay Rs 59850
S.P=C.P(1-loss℅/100)
=70000(1-5/100)
=70000(19/20)
=66500
for second farmer
S.P=C.P(1-loss℅/100)
=66500(1-10/100
=66500(9/10)
=59850
So the third farmer had to pay Rs 59850
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